____________________________________ Recall that in order to solve the “arched doorway” problem a variation of the Pythagorean Theorem was used. If this formula is used to test values of the parabola the values would be taken as the chord in the xdirection and the radius in the ydirection. This works for small values and also checks by the Pythagorean Theorem, but we know just by first observation that although both equations are satisfied, the values are too large. This leads the observer to test values with the chord in the xdirection and radius with the yvalue. (Note all values are relative to the parabolas origin which is at (4,0). So the x value would be added by 4.) Here is a random test value: a chord of 28 plugged into the equation x^2+8x+1624 = 0 Four is added since the parabola is shifted 4 units to the left then using the Quadratic Equation to solve we get 44 or 39.1918 Here 44 is used and plugged into the Pythagorean Theorem used to solve the “arched doorway” problem First the "arched doorway" problem for reference: 2.5r = 5.5628 r = 2.22512
____________________________________ for 44 radius and 28 chord X = 40.9878 That is the value of the length perpendicular to the bottom of the chord
It checks. And it should be the smallest circle that encompasses a chord of length 28 units!
